Correcting Errors

Segment 1: Alphabet List

Intended behavior: create a list of characters from the string contained in the variable alphabet

Code:

%%js

var alphabet = "abcdefghijklmnopqrstuvwxyz";
var alphabetList = [];

for (var i = 0; i < alphabet.length; i++) {
	alphabetList.push(alphabet[i]);
}

console.log(alphabetList);

Change 10 to alphabet.length in order for the “for” loop to run as long as “i” is less than the length of the alphabet string. Change (i) to (alphabet[i]) so that inside the loop, each letter is pushed into the alphabetlist.

Segment 2: Numbered Alphabet

Intended behavior: print the number of a given alphabet letter within the alphabet. For example:

"_" is letter number _ in the alphabet

Where the underscores (_) are replaced with the letter and the position of that letter within the alphabet (e.g. a=1, b=2, etc.)

Code:

%%js

var alphabet = "abcdefghijklmnopqrstuvwxyz";
var alphabetList = [];

for (var i = 0; i < alphabet.length; i++) {
    alphabetList.push(alphabet[i]);
}

let letterNumber = 5;

for (var i = 0; i < alphabetList.length; i++) {
	if (i + 1 === letterNumber) {
		console.log(alphabetList[i] + " is letter number " + letterNumber + " in the alphabet")
	}
}



// Should output:
// "e" is letter number 5 in the alphabet

Change alphabetList to alphabetList.length in the second “for” loop to interate through the alphabetList. Change (i === letterNumber) to (i + 1 === letterNumber) in order to account for zero based counting.

Segment 3: Odd Numbers

Intended behavior: print a list of all the odd numbers below 10

Code:

%%js

let odds = [];
let i = 1;

while (i < 10) {
  odds.push(i);
  i += 2;
}

console.log(odds);

Change all “evens” to “odds” because we want odd numbers, not even Change i = 0 to i = 1 to start with the first odd number below 10 (1) Change i <= 10 to i < 10 because 10 is an even number

Correcting Errors